LynnBlakeGolf Forums - View Single Post - Fun Probability problem Thread: Fun Probability problem View Single Post #13 02-20-2007, 03:29 PM Mathew Inactive User Join Date: Jan 2005 Posts: 833 Originally Posted by armourall What would you think if I stated it like this... Original Selection:The player originally picked goat 1.The player originally picked goat 2.The player originally picked the car.Chances of originally selecting the car: 1 in 3. Correct... Quote: Second Selection:[list=1][*]The player originally picked goat 1. The door with goat 2 is revealed. The remaining door has the car. Correct Quote: [*]The player originally picked goat 2. The door with goat 1 is revealed. The remaining door has the car. Correct Quote: The player originally picked the car. The door with goat 1 is revealed. The remaining door has goat 2.The player originally picked the car. The door with goat 2 is revealed. The remaining door has goat 1.Chances of switching and selecting the car: 2 in 4 (1 in 2) Nope - there is only 1 car behind the doors not two.... Just because there are four permutations of what can occur doesn't mean you have four choices. It really doesn't matter if you eliminate goat 1 or goat 2 when you have picked the car. If you switch, you will lose either way.... Make this any easier to understand ? Mathew View Public Profile Send a private message to Mathew Find all posts by Mathew